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For the following quadratic equation, find the discriminant.

-4x^(2)+18 x+112=2x
Answer:

For the following quadratic equation, find the discriminant.\newline4x2+18x+112=2x -4 x^{2}+18 x+112=2 x \newlineAnswer:

Full solution

Q. For the following quadratic equation, find the discriminant.\newline4x2+18x+112=2x -4 x^{2}+18 x+112=2 x \newlineAnswer:
  1. Rewrite in Standard Form: First, we need to rewrite the quadratic equation in standard form, which is ax2+bx+c=0ax^2 + bx + c = 0.
    4x2+18x+112=2x-4x^2 + 18x + 112 = 2x
    Subtract 2x2x from both sides to get:
    4x2+16x+112=0-4x^2 + 16x + 112 = 0
  2. Identify Coefficients: Now that we have the quadratic equation in standard form, we can identify the coefficients aa, bb, and cc.a=4a = -4, b=16b = 16, and c=112c = 112
  3. Calculate Discriminant: The discriminant of a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0 is given by the formula D=b24acD = b^2 - 4ac. Let's calculate the discriminant using the identified coefficients: D=(16)24(4)(112)D = (16)^2 - 4(-4)(112)
  4. Perform Calculations: Now, perform the calculations:\newlineD=2564(4)(112)D = 256 - 4(-4)(112)\newlineD=256+1792D = 256 + 1792\newlineD=2048D = 2048

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