Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

For the following equation, what is the instantaneous rate of change at 
x=-1?

f(x)=-3x^(2)+2
Answer:

For the following equation, what is the instantaneous rate of change at x=1? x=-1 ? \newlinef(x)=3x2+2 f(x)=-3 x^{2}+2 \newlineAnswer:

Full solution

Q. For the following equation, what is the instantaneous rate of change at x=1? x=-1 ? \newlinef(x)=3x2+2 f(x)=-3 x^{2}+2 \newlineAnswer:
  1. Calculate Derivative: To find the instantaneous rate of change of the function at a specific point, we need to calculate the derivative of the function. The derivative of a function gives us the slope of the tangent line at any point, which is the instantaneous rate of change.
  2. Apply Power Rule: The function given is f(x)=3x2+2f(x) = -3x^2 + 2. To find its derivative, we use the power rule, which states that the derivative of xnx^n is nx(n1)n\cdot x^{(n-1)}. Applying this rule to each term in the function, we get:\newlinef(x)=ddx(3x2)+ddx(2)f'(x) = \frac{d}{dx}(-3x^2) + \frac{d}{dx}(2)\newlinef(x)=32x(21)+0f'(x) = -3 \cdot 2x^{(2-1)} + 0\newlinef(x)=6xf'(x) = -6x
  3. Find Instantaneous Rate: Now that we have the derivative, we can find the instantaneous rate of change at x=1x = -1 by plugging 1-1 into the derivative function.\newlinef(1)=6(1)f'(-1) = -6*(-1)\newlinef(1)=6f'(-1) = 6

More problems from Find derivatives using logarithmic differentiation