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Five students, Leah, Fawzia, Yusuf, Hailey, and Autumn, line up one behind the other. How many different ways can they stand in line?
Answer:

Five students, Leah, Fawzia, Yusuf, Hailey, and Autumn, line up one behind the other. How many different ways can they stand in line? $\newline$ Answer:

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Experimental probability

Full solution

Q. Five students, Leah, Fawzia, Yusuf, Hailey, and Autumn, line up one behind the other. How many different ways can they stand in line?

\newline

Answer:

Identify Problem: Identify the problem. $\newline$ We need to find the number of different arrangements for $5$ students standing in line. This is a permutation problem where order matters.
Determine Formula: Determine the formula to use. $\newline$ The number of ways to arrange $n$ distinct objects in a sequence is given by $n$ factorial, denoted as $n!$ .
Apply Formula: Apply the formula to the given problem. $\newline$ Since there are $5$ students, we need to calculate $5!$ ( $5$ factorial). $\newline$ $5! = 5 \times 4 \times 3 \times 2 \times 1$
Perform Calculation: Perform the calculation. $5! = 5 \times 4 \times 3 \times 2 \times 1 = 120$
Conclude Answer: Conclude with the final answer. $\newline$ There are $120$ different ways the five students can stand in line.

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