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Find $x$ any $y$ and draw a grap of $y=(x-1)^{2} +3$

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Sin, cos, and tan of special angles

Full solution

Q. Find

x

any

y

and draw a grap of

y=(x-1)^{2} +3

Pick $x$ values: To find the values of $x$ and $y$ , we need to pick some $x$ values and plug them into the equation to get the corresponding $y$ values.
Calculate corresponding y values: Let's pick $x = 0$ and plug it into the equation: $y = (0 - 1)^2 + 3 = (-1)^2 + 3 = 1 + 3 = 4$ .
Plot points on coordinate plane: Now let's pick $x = 1$ : $y = (1 - 1)^2 + 3 = 0^2 + 3 = 0 + 3 = 3$ .
Sketch parabola: And let's pick $x = 2$ : $y = (2 - 1)^2 + 3 = 1^2 + 3 = 1 + 3 = 4$ .
Sketch parabola: And let's pick $x = 2$ : $y = (2 - 1)^2 + 3 = 1^2 + 3 = 1 + 3 = 4$ .To draw the graph, we plot the points $(0, 4)$ , $(1, 3)$ , and $(2, 4)$ on a coordinate plane and sketch the parabola that goes through these points.
Sketch parabola: And let's pick $x = 2$ : $y = (2 - 1)^2 + 3 = 1^2 + 3 = 1 + 3 = 4$ .To draw the graph, we plot the points $(0, 4)$ , $(1, 3)$ , and $(2, 4)$ on a coordinate plane and sketch the parabola that goes through these points.The graph is a parabola that opens upwards with vertex at $(1, 3)$ because the coefficient of $(x - 1)^2$ is positive.

More problems from Sin, cos, and tan of special angles

Question

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\newline

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\newline

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Question

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\newline

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\newline

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Question

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\newline

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\newline

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\newline

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