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Find the
y-coordinate of the
y-intercept of the polynomial function defined below.

f(x)=4x-4x^(2)+5x^(5)+3x^(3)+5x^(4)
Answer:

Find the $y$ -coordinate of the $y$ -intercept of the polynomial function defined below. $\newline$ $f(x)=4 x-4 x^{2}+5 x^{5}+3 x^{3}+5 x^{4}$ $\newline$ Answer:

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Reflections of functions

Full solution

Q. Find the

y

-coordinate of the

y

-intercept of the polynomial function defined below.

\newline

f(x)=4 x-4 x^{2}+5 x^{5}+3 x^{3}+5 x^{4}

\newline

Answer:

Evaluate $f(x)$ at $x=0$ : To find the $y$ -coordinate of the $y$ -intercept of the function $f(x)$ , we need to evaluate $f(x)$ when $x = 0$ .
Substitute $x=0$ into $f(x)$ : Substitute $x = 0$ into the polynomial function $f(x) = 4x - 4x^2 + 5x^5 + 3x^3 + 5x^4$ .
Calculate $f(0)$ : $f(0) = 4(0) - 4(0)^2 + 5(0)^5 + 3(0)^3 + 5(0)^4$ .
Simplify the expression: Simplify the expression by calculating the value of each term when $x = 0$ . $f(0) = 0 - 0 + 0 + 0 + 0.$
Final result: The result of $f(0)$ is $0$ , which means the y-coordinate of the y-intercept is $0$ .

More problems from Reflections of functions

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Question

What kind of transformation converts the graph of

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\text{[A]translation 10 units left}

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\text{[B]translation 10 units right}

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Question

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Question

\lim _{x \rightarrow \frac{\pi}{4}} \cos (x)=?

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1

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1

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Question

Tess tried to solve the differential equation

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\newline

\frac{d y}{d x}=2 x y-6 x

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1

\quad \frac{d y}{d x}=(y-3) 2 x

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2

\quad \int \frac{1}{y-3} d y=\int 2 x d x

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5

\quad|y-3|=e^{x^{2}}+C_{1}

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7

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(A) Tess's work is correct.

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4

is incorrect. The right-hand side of the equation should be

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7

is incorrect. Tess didn't account for adding

3

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Question

Aditya tried to solve the differential equation

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\newline

\frac{d y}{d x}=6 x-30

\newline

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\quad \int 30 d y=\int 6 x d x

\newline

2

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of the following expressions represents the distance between the sandbag and the target?

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2

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Question

f(x) = -(x+1)(x+7)

\newline

The function represents a parabola in the

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\newline

1

\newline

f(x) = -(x+4)^{2}+9

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Determine whether the function

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\newline

f(x)

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\newline

f(x)

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