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Find the y-coordinate of the y-intercept of the polynomial function defined below. f(x)=2(x-1)^(2)(x+4) Answer:

Find the y y -coordinate of the y y -intercept of the polynomial function defined below.\newlinef(x)=2(x−1)2(x+4) f(x)=2(x-1)^{2}(x+4) \newlineAnswer:

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Full solution

Q. Find the y y -coordinate of the y y -intercept of the polynomial function defined below.\newlinef(x)=2(x−1)2(x+4) f(x)=2(x-1)^{2}(x+4) \newlineAnswer:
  1. Evaluate f(0)f(0): To find the y-coordinate of the y-intercept of the function f(x)f(x), we need to evaluate f(x)f(x) when x=0x = 0.\newlineCalculation: f(0)=2(0−1)2(0+4)f(0) = 2(0 - 1)^2(0 + 4)
  2. Simplify expression: Simplify the expression by calculating the powers and multiplication.\newlineCalculation: f(0)=2(−1)2×4=2×1×4=8f(0) = 2(-1)^2 \times 4 = 2 \times 1 \times 4 = 8
  3. Find y-intercept: The y-coordinate of the y-intercept is the value of f(0)f(0), which we have found to be 88.

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