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Find the
y-coordinate of the
y-intercept of the polynomial function defined below.

f(x)=2(x^(2)+3)(x-2)(x-5)
Answer:

Find the $y$ -coordinate of the $y$ -intercept of the polynomial function defined below. $\newline$ $f(x)=2\left(x^{2}+3\right)(x-2)(x-5)$ $\newline$ Answer:

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Reflections of functions

Full solution

Q. Find the

y

-coordinate of the

y

-intercept of the polynomial function defined below.

\newline

f(x)=2\left(x^{2}+3\right)(x-2)(x-5)

\newline

Answer:

Evaluate at $x = 0$ : To find the $y$ -coordinate of the $y$ -intercept of the function, we need to evaluate the function at $x = 0$ , because the $y$ -intercept occurs where the graph of the function crosses the $y$ -axis, and the $x$ -coordinate of any point on the $y$ -axis is $0$ .
Substitute $x = 0$ : Substitute $x = 0$ into the function $f(x)$ to find the $y$ -coordinate of the $y$ -intercept. $\newline$ $f(0) = 2(0^2 + 3)(0 - 2)(0 - 5)$
Simplify expression: Simplify the expression by performing the operations. $f(0) = 2(3)(-2)(-5)$
Calculate product: Calculate the product of the numbers. $\newline$ $f(0) = 2 \times 3 \times 2 \times 5$ $\newline$ $f(0) = 6 \times 2 \times 5$ $\newline$ $f(0) = 12 \times 5$ $\newline$ $f(0) = 60$

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Question

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\text{[A]translation 10 units left}

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Question

\lim _{x \rightarrow \frac{\pi}{4}} \cos (x)=?

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1

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Question

Tess tried to solve the differential equation

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\frac{d y}{d x}=2 x y-6 x

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\quad \frac{d y}{d x}=(y-3) 2 x

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5

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7

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7

is incorrect. Tess didn't account for adding

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Question

Aditya tried to solve the differential equation

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\newline

\frac{d y}{d x}=6 x-30

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of the following expressions represents the distance between the sandbag and the target?

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2

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Question

f(x) = -(x+1)(x+7)

\newline

The function represents a parabola in the

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1

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f(x)

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