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Find the values using the order of operations.

40÷2-2×7-(30-26)×(-9)^(2)=

Find the values using the order of operations. $\newline$ $40 \div 2-2 \times 7-(30-26) \times(-9)^{2}=$

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Change of base formula

Full solution

Q. Find the values using the order of operations.

\newline

40 \div 2-2 \times 7-(30-26) \times(-9)^{2}=

Calculate Exponent: First, calculate the exponent $(-9)^{2}$ . $\$(-9)^{2} = 81$ )
Perform Subtraction: Next, do the operations inside the parentheses $(30-26)$ . $\newline$ $30-26 = 4$
Multiply Results: Now, multiply the result of the parentheses by the exponent result. $4\times81 = 324$
Do Multiplication: Then, do the multiplication $2\times7$ . $2\times7 = 14$
Divide Numbers: Now, divide $40$ by $2$ . $\newline$ $40\div2 = 20$
Subtract Results: Subtract the multiplication result from the division result. $20-14 = 6$
Final Subtraction: Finally, subtract the result of the multiplication of the parentheses and the exponent from the previous result. $\newline$ $6-(324) = -318$

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