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Find the values of xx for which the given function is concave​ up, the values of xx for which it is concave​ down, and any points of inflection. y=x4+12x312x+13y=-x^4+12x^3-12x+13. What​ is/are the​ point(s) of inflection of​ yy? Select the correct choice below​ and, if​ necessary, fill in the answer box to complete your choice.\newlineA. enter your response here ​(Type an ordered pair. Use a comma to separate answers as​ needed.)\newlineB. There are no points of inflection.

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Q. Find the values of xx for which the given function is concave​ up, the values of xx for which it is concave​ down, and any points of inflection. y=x4+12x312x+13y=-x^4+12x^3-12x+13. What​ is/are the​ point(s) of inflection of​ yy? Select the correct choice below​ and, if​ necessary, fill in the answer box to complete your choice.\newlineA. enter your response here ​(Type an ordered pair. Use a comma to separate answers as​ needed.)\newlineB. There are no points of inflection.
  1. Calculate Second Derivative: Now, calculate the second derivative: y=12x2+72xy'' = -12x^2 + 72x.
  2. Find Points of Inflection: To find points of inflection, set the second derivative equal to zero and solve for xx: 12x2+72x=0-12x^2 + 72x = 0. Factor out 12x12x: 12x(x+6)=012x(-x + 6) = 0.
  3. Solve for Potential Points: Solve for xx: x=0x = 0 or x=6x = 6. These are the potential points of inflection.
  4. Determine Concavity: To determine concavity, test intervals around the critical points 00 and 66 in the second derivative. Pick test points like x=1x = -1, x=3x = 3, and x=7x = 7 and plug them into yy''.
  5. Test Intervals in Second Derivative: For x=1x = -1: y(1)=12(1)2+72(1)=1272=84y''(-1) = -12(-1)^2 + 72(-1) = -12 - 72 = -84, which is less than 00, so the function is concave down on (,0)(-\infty, 0).
  6. Concave Down on (,0)(-\infty, 0): For x=3x = 3: y(3)=12(3)2+72(3)=108+216=108y''(3) = -12(3)^2 + 72(3) = -108 + 216 = 108, which is greater than 00, so the function is concave up on (0,6)(0, 6).
  7. Concave Up on (0,6)(0, 6): For x=7x = 7: y(7)=12(7)2+72(7)=588+504=84y''(7) = -12(7)^2 + 72(7) = -588 + 504 = -84, which is less than 00, so the function is concave down on (6,)(6, \infty).
  8. Concave Down on (6,):</b>Tofindthe$y(6, \infty):</b> To find the \$y-coordinates of the points of inflection, plug x=0x = 0 and x=6x = 6 into the original function yy. For x=0x = 0: y(0)=(0)4+12(0)312(0)+13=13y(0) = -(0)^4 + 12(0)^3 - 12(0) + 13 = 13. For x=6x = 6: y(6)=(6)4+12(6)312(6)+13=1296+259272+13=1237y(6) = -(6)^4 + 12(6)^3 - 12(6) + 13 = -1296 + 2592 - 72 + 13 = 1237.

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