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Find the square. Simplify your answer.\newline(3g+4)2(3g + 4)^2

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Multiply two binomials: special casesright chevron icon

Full solution

Q. Find the square. Simplify your answer.\newline(3g+4)2(3g + 4)^2
  1. Identify special case: Identify the special case for squaring a binomial.\newlineThe expression (3g+4)2(3g + 4)^2 is in the form of (a+b)2(a + b)^2.\newlineSpecial case: (a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2
  2. Identify values of aa and bb: Identify the values of aa and bb in the expression (3g+4)2(3g + 4)^2. Compare (3g+4)2(3g + 4)^2 with (a+b)2(a + b)^2. a=3ga = 3g b=4b = 4
  3. Apply binomial square formula: Apply the square of a binomial formula to expand (3g+4)2(3g + 4)^2.(a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2(3g+4)2=(3g)2+2(3g)(4)+42(3g + 4)^2 = (3g)^2 + 2(3g)(4) + 4^2
  4. Simplify expression: Simplify the expression (3g)2+2(3g)(4)+42.(3g)^2 + 2(3g)(4) + 4^2.(3g)2+2(3g)(4)+42(3g)^2 + 2(3g)(4) + 4^2=(3g⋅3g)+(2⋅3g⋅4)+(4⋅4)= (3g \cdot 3g) + (2 \cdot 3g \cdot 4) + (4 \cdot 4)=9g2+24g+16= 9g^2 + 24g + 16

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