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Find the smallest pair of 4-digit numbers such that the difference between them is 303 and their HCF is 101.
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Find the smallest pair of 44-digit numbers such that the difference between them is 303303 and their HCF is 101101. Show your steps.

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Q. Find the smallest pair of 44-digit numbers such that the difference between them is 303303 and their HCF is 101101. Show your steps.
  1. Identify Numbers: Since the HCF of the two numbers is 101101, both numbers must be multiples of 101101. Let's denote the smaller number as 101a101a and the larger number as 101b101b, where aa and bb are integers.
  2. Set Up Equation: The difference between the two numbers is given as 303303, which is also a multiple of 101101 (since 303=101×3303 = 101 \times 3). We can set up the equation 101b101a=303101b - 101a = 303 to find the relationship between aa and bb.
  3. Solve for Relationship: Dividing both sides of the equation by 101101, we get ba=3b - a = 3. This means that the two integers aa and bb must be 33 units apart.
  4. Find Smallest aa: Since we are looking for the smallest 44-digit numbers, we want to find the smallest possible value for aa such that 101a101a is a 44-digit number. The smallest 44-digit number is 10001000, so we need to find the smallest integer aa such that 101a1000101a \geq 1000.
  5. Calculate Minimum aa: Dividing 10001000 by 101101, we get approximately 9.99.9. Since aa must be an integer, the smallest possible value for aa that makes 101a101a a 44-digit number is 1010.
  6. Determine Values of aa and bb: Now that we have a=10a = 10, we can find bb by adding 33 to aa, giving us b=10+3=13b = 10 + 3 = 13.
  7. Calculate Numbers: The two numbers are therefore 101a=101×10=1010101a = 101 \times 10 = 1010 and 101b=101×13=1313101b = 101 \times 13 = 1313.
  8. Verify Solution: We check that the difference between the two numbers is 13131010=3031313 - 1010 = 303, which matches the condition given in the problem.

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