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Find the slope of the line containing the points $(6,-5)$ and $(-8,8)$ .

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Find the magnitude of a three-dimensional vector

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Q. Find the slope of the line containing the points

(6,-5)

and

(-8,8)

.

Identify Slope Formula: To find the slope of the line containing two points, we use the slope formula, which is $(y_2 - y_1) / (x_2 - x_1)$ , where $(x_1, y_1)$ and $(x_2, y_2)$ are the coordinates of the two points.
Plug in Coordinates: Let's plug in the coordinates of the points into the slope formula. For point $(6,-5)$ , let's call it $(x_1, y_1)$ , and for point $(-8,8)$ , let's call it $(x_2, y_2)$ . So, slope $m = \frac{8 - (-5)}{-8 - 6}$ .
Perform Subtraction: Now, let's perform the subtraction in the numerator and the denominator. $\newline$ $m = (8 + 5) / (-8 - 6)$ . $\newline$ $m = 13 / (-14)$ .
Simplify Fraction: We simplify the fraction to get the slope of the line. $m = -\frac{13}{14}$ .

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