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Find the quadratic polynomial that completes the factorization. \newlinew3+8=(w+2)(_____)w^3 + 8 = (w + 2)(\_\_\_\_\_)

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Q. Find the quadratic polynomial that completes the factorization. \newlinew3+8=(w+2)(_____)w^3 + 8 = (w + 2)(\_\_\_\_\_)
  1. Factorization of sum of cubes: We know that w3+8w^3 + 8 is a sum of cubes, which factors as (w+2)(w22w+4)(w + 2)(w^2 - 2w + 4).
  2. Multiplication check: Now we need to check if our factorization is correct by multiplying (w+2)(w22w+4)(w + 2)(w^2 - 2w + 4).
  3. Combining like terms: w + \(2)(w^22 - 22w + 44) = w^33 - 22w^22 + 44w + 22w^22 - 44w + 88\
  4. Final verification: Combine like terms: w3+0w2+0w+8=w3+8w^3 + 0w^2 + 0w + 8 = w^3 + 8.
  5. Final verification: Combine like terms: w3+0w2+0w+8=w3+8w^3 + 0w^2 + 0w + 8 = w^3 + 8.Since the original expression is w3+8w^3 + 8, our factorization is correct.

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