Find the product. Simplify your answer. (4x + 1)(3x + 2) ______

Apply Distributive Property: Apply the distributive property to multiply the two binomials (4x + 1) and (3x + 2). Distribute each term in the first binomial across the second binomial. (4x + 1)(3x + 2) = 4x(3x + 2) + 1(3x + 2)Multiply 4x by Second Binomial: Multiply 4x by each term in the second binomial (3x + 2). 4x(3x + 2) = 4x * 3x + 4x * 2 = 12x^2 + 8xMultiply 1 by Second Binomial: Multiply 1 by each term in the second binomial (3x + 2). 1(3x + 2) = 1 * 3x + 1 * 2 = 3x + 2Combine Results: Combine the results from Step 2 and Step 3. (4x + 1)(3x + 2) = 12x^2 + 8x + 3x + 2Combine Like Terms: Combine like terms. 12x^2 + 8x + 3x + 2 = 12x^2 + (8x + 3x) + 2 = 12x^2 + 11x + 2

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Find the product. Simplify your answer. $\newline$ $(4x + 1)(3x + 2)$

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Math Problems

Algebra 1

Multiply two binomials

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Q. Find the product. Simplify your answer.

\newline

(4x + 1)(3x + 2)

Apply Distributive Property: Apply the distributive property to multiply the two binomials $(4x + 1)$ and $(3x + 2)$ . Distribute each term in the first binomial across the second binomial. $(4x + 1)(3x + 2) = 4x(3x + 2) + 1(3x + 2)$
Multiply $4$ x by Second Binomial: Multiply $4x$ by each term in the second binomial $(3x + 2)$ . $\newline$ $4x(3x + 2) = 4x \times 3x + 4x \times 2$ $\newline$ $= 12x^2 + 8x$
Multiply $1$ by Second Binomial: Multiply $1$ by each term in the second binomial $(3x + 2)$ . $\newline$ $1(3x + 2) = 1 \times 3x + 1 \times 2$ $\newline$ $= 3x + 2$
Combine Results: Combine the results from Step $2$ and Step $3$ . $\newline$ $(4x + 1)(3x + 2) = 12x^2 + 8x + 3x + 2$
Combine Like Terms: Combine like terms. $\newline$ $12x^2 + 8x + 3x + 2 = 12x^2 + (8x + 3x) + 2$ $\newline$ $= 12x^2 + 11x + 2$