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Find the product. Simplify your answer.\newline(4w−3)(4w+3)(4w - 3)(4w + 3)

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Full solution

Q. Find the product. Simplify your answer.\newline(4w−3)(4w+3)(4w - 3)(4w + 3)
  1. Identify values: Identify the values of aa and bb. Compare (4w−3)(4w+3)(4w - 3)(4w + 3) with (a−b)(a+b)(a - b)(a + b). a=4wa = 4w b=3b = 3
  2. Apply formula: Apply the difference of squares formula to expand (4w−3)(4w+3)(4w - 3)(4w + 3).\newline(a−b)(a+b)=a2−b2(a - b)(a + b) = a^2 - b^2\newline(4w−3)(4w+3)=(4w)2−(3)2(4w - 3)(4w + 3) = (4w)^2 - (3)^2
  3. Simplify expression: Simplify (4w)2−(3)2.(4w)^2 - (3)^2.(4w)2−(3)2=(4w×4w)−(3×3)(4w)^2 - (3)^2 = (4w \times 4w) - (3 \times 3)=16w2−9= 16w^2 - 9

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