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Find the product. Simplify your answer.\newline(3y−4)(3y+4)(3y - 4)(3y + 4)

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Full solution

Q. Find the product. Simplify your answer.\newline(3y−4)(3y+4)(3y - 4)(3y + 4)
  1. Calculate Squares: Now, calculate the squares of both terms, where a=3ya = 3y and b=4b = 4. (3y)2=9y2(3y)^2 = 9y^2 and (4)2=16(4)^2 = 16.
  2. Substitute Squared Terms: Substitute the squared terms into the difference of squares formula. \newline(3y−4)(3y+4)=(3y)2−(4)2=9y2−16(3y - 4)(3y + 4) = (3y)^2 - (4)^2 = 9y^2 - 16.
  3. Final Answer: The expression is already simplified, so we have our final answer. 9y2−169y^2 - 16 is the simplified product of (3y−4)(3y+4)(3y - 4)(3y + 4).

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