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Find the product. Simplify your answer.\newline(3v+3)(4v−2)(3v + 3)(4v - 2)

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Full solution

Q. Find the product. Simplify your answer.\newline(3v+3)(4v−2)(3v + 3)(4v - 2)
  1. Apply Distributive Property: Apply the distributive property to multiply the two binomials (3v+3)(3v + 3) and (4v−2)(4v - 2).(3v+3)(4v−2)=3v(4v−2)+3(4v−2)(3v + 3)(4v - 2) = 3v(4v - 2) + 3(4v - 2)
  2. Multiply 3v3v by Binomial: Multiply 3v3v by each term in the binomial (4v−2)(4v - 2).\newline3v(4v−2)=3v×4v−3v×23v(4v - 2) = 3v \times 4v - 3v \times 2\newline=12v2−6v= 12v^2 - 6v
  3. Multiply 33 by Binomial: Multiply 33 by each term in the binomial (4v−2)(4v - 2). \newline3(4v−2)=3×4v−3×23(4v - 2) = 3 \times 4v - 3 \times 2\newline=12v−6= 12v - 6
  4. Combine Results: Combine the results from the previous steps to get the full expression.\newline(3v+3)(4v−2)=12v2−6v+12v−6(3v + 3)(4v - 2) = 12v^2 - 6v + 12v - 6
  5. Combine Like Terms: Combine like terms in the expression.\newline12v2−6v+12v−6=12v2+(12v−6v)−612v^2 - 6v + 12v - 6 = 12v^2 + (12v - 6v) - 6\newline=12v2+6v−6= 12v^2 + 6v - 6

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