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Find the product. Simplify your answer.\newline3j2(3j2+2j+1)3j^2(-3j^2 + 2j + 1)

Full solution

Q. Find the product. Simplify your answer.\newline3j2(3j2+2j+1)3j^2(-3j^2 + 2j + 1)
  1. Multiply Terms: Multiply 3j23j^2 by 3j2-3j^2 to get the first term of the product.\newline3j2×3j2=9j43j^2 \times -3j^2 = -9j^4
  2. Calculate First Term: Multiply 3j23j^2 by 2j2j to get the second term of the product.\newline3j2×2j=6j33j^2 \times 2j = 6j^3
  3. Calculate Second Term: Multiply 3j23j^2 by 11 to get the third term of the product.\newline3j2×1=3j23j^2 \times 1 = 3j^2
  4. Calculate Third Term: Combine the results from the previous steps to write the simplified form of the product.\newlineThe product is 9j4+6j3+3j2-9j^4 + 6j^3 + 3j^2.

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