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Find the product. Simplify your answer. \newline2j(4j2+5)-2j(-4j^2 + 5)

Full solution

Q. Find the product. Simplify your answer. \newline2j(4j2+5)-2j(-4j^2 + 5)
  1. Distribute 2j-2j: We need to distribute 2j-2j to both terms inside the parentheses: 4j2-4j^2 and +5+5.\newline2j(4j2+5)=2j(4j2)+2j(5)-2j(-4j^2 + 5) = -2j(-4j^2) + -2j(5)
  2. Simplify 4j2-4j^2: Now, simplify 2j(4j2)-2j(-4j^2).2j(4j2)=(2×4)×(j×j2)=8j3-2j(-4j^2) = (-2 \times -4) \times (j \times j^2) = 8j^3
  3. Simplify 2j(5)-2j(5): Next, simplify 2j(5)-2j(5).\newline2j(5)=2×5×j=10j-2j(5) = -2 \times 5 \times j = -10j
  4. Combine results: Combine the results from the previous steps to get the final simplified expression.\newline2j(4j2+5)=8j310j-2j(-4j^2 + 5) = 8j^3 - 10j

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