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Find the line's slope and a point on the line. y-2=3(x+1) slope: ◻ point on the line: (ㅁ,ㅁ)

Find the line's slope and a point on the line.\newliney−2=3(x+1) y-2=3(x+1) \newlineslope: □ \square \newlinepoint on the line: (ㅁ,ㅁ)

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Full solution

Q. Find the line's slope and a point on the line.\newliney−2=3(x+1) y-2=3(x+1) \newlineslope: □ \square \newlinepoint on the line: (ㅁ,ㅁ)
  1. Rewrite Equation: Rewrite the equation in slope-intercept form y=mx+by = mx + b to find the slope.y−2=3(x+1)y - 2 = 3(x + 1)y=3x+3+2y = 3x + 3 + 2y=3x+5y = 3x + 5
  2. Find Slope: Identify the slope from the equation y=3x+5y = 3x + 5.\newlineSlope (mm) = 33
  3. Identify Slope: Identify a point on the line using the equation y=3x+5y = 3x + 5.\newlineSubstitute x=0x = 0 into the equation:\newliney=3(0)+5y = 3(0) + 5\newliney=5y = 5\newlinePoint on the line: (0,5)(0, 5)

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