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Find the line's slope and a point on the line.

y+5=-(3)/(2)(x-1)

Find the line's slope and a point on the line.\newliney+5=32(x1) y+5=-\frac{3}{2}(x-1)

Full solution

Q. Find the line's slope and a point on the line.\newliney+5=32(x1) y+5=-\frac{3}{2}(x-1)
  1. Rewrite equation in slope-intercept form: Rewrite the equation in slope-intercept form y=mx+by = mx + b, where mm is the slope.y+5=(32)(x1)y + 5 = -\left(\frac{3}{2}\right)(x - 1)y=(32)(x1)5y = -\left(\frac{3}{2}\right)(x - 1) - 5
  2. Distribute slope across expression: Distribute the slope 32-\frac{3}{2} across (x1)(x - 1).y=32x+325y = -\frac{3}{2}x + \frac{3}{2} - 5Combine like terms.y=32x72y = -\frac{3}{2}x - \frac{7}{2}
  3. Identify slope from equation: Identify the slope mm from the equation y=mx+by = mx + b.\newlineSlope m=(32)m = -\left(\frac{3}{2}\right)
  4. Find point on the line: Find a point on the line by substituting x=1x = 1 into the equation.\newliney=(32)(1)(72)y = -\left(\frac{3}{2}\right)(1) - \left(\frac{7}{2}\right)\newliney=(32)(72)y = -\left(\frac{3}{2}\right) - \left(\frac{7}{2}\right)\newliney=102y = -\frac{10}{2}\newliney=5y = -5

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