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Find the inverse of the function.\newliney=5x+1y = 5x + 1\newlineWrite your answer in the form ax+bax + b. Simplify any fractions.\newliney = ______

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Full solution

Q. Find the inverse of the function.\newliney=5x+1y = 5x + 1\newlineWrite your answer in the form ax+bax + b. Simplify any fractions.\newliney = ______
  1. Swap xx and yy: To find the inverse of the function, we first swap xx and yy. This gives us the equation x=5y+1x = 5y + 1.
  2. Solve for yy: Next, we need to solve for yy. To do this, we subtract 11 from both sides of the equation to isolate the term with yy. This gives us x−1=5y+1−1x - 1 = 5y + 1 - 1.
  3. Isolate y: Simplifying the equation, we get x−1=5yx - 1 = 5y. Now we need to isolate yy by dividing both sides of the equation by 55.
  4. Final result: Dividing both sides by 55 gives us (x−1)/5=y(x - 1)/5 = y, or y=(1/5)x−1/5y = (1/5)x - 1/5.

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