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Find the inverse of the function.\newliney=2x+8y = -2x + 8\newlineWrite your answer in the form ax+bax + b. Simplify any fractions.\newliney=y = ______

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Q. Find the inverse of the function.\newliney=2x+8y = -2x + 8\newlineWrite your answer in the form ax+bax + b. Simplify any fractions.\newliney=y = ______
  1. Swap xx and yy: To find the inverse of the function, we first swap xx and yy. This gives us the equation x=2y+8x = -2y + 8.
  2. Add and isolate terms: Next, we need to solve for yy. To do this, we'll add 2y2y to both sides of the equation to get x+2y=8x + 2y = 8.
  3. Divide by 22: Now, we subtract xx from both sides to isolate the terms with yy on one side. This gives us 2y=8x2y = 8 - x.
  4. Distribute division: To solve for yy, we divide both sides of the equation by 22. This simplifies to y=8x2y = \frac{8 - x}{2}.
  5. Simplify fractions: We can further simplify the equation by distributing the division across the terms in the numerator. This gives us y=82x2y = \frac{8}{2} - \frac{x}{2}.
  6. Rewrite in desired form: Simplifying the fractions, we get y=4(12)xy = 4 - \left(\frac{1}{2}\right)x. To match the form ax+bax + b, we rewrite this as y=(12)x+4y = -\left(\frac{1}{2}\right)x + 4.

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