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Find the inverse of the function.\newliney=2x+1y = -2x + 1\newlineWrite your answer in the form ax+bax + b. Simplify any fractions.\newliney=y = ______

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Q. Find the inverse of the function.\newliney=2x+1y = -2x + 1\newlineWrite your answer in the form ax+bax + b. Simplify any fractions.\newliney=y = ______
  1. Swap xx and yy: To find the inverse of the function, we first swap xx and yy. This gives us the equation x=2y+1x = -2y + 1.
  2. Add and isolate yy: Next, we need to solve for yy. To do this, we'll add 2y2y to both sides of the equation to get x+2y=1x + 2y = 1.
  3. Divide by 22: Now, we subtract xx from both sides to isolate the term with yy on one side: 2y=1x2y = 1 - x.
  4. Simplify numerator: To solve for yy, we divide both sides of the equation by 22. This gives us y=1x2y = \frac{1 - x}{2}.
  5. Rearrange terms: We can simplify this further by distributing the division across the terms in the numerator: y=12x2y = \frac{1}{2} - \frac{x}{2}.
  6. Rearrange terms: We can simplify this further by distributing the division across the terms in the numerator: y=12x2y = \frac{1}{2} - \frac{x}{2}.Finally, we can write the inverse function in the form ax+bax + b by rearranging the terms: y=12x+12y = -\frac{1}{2}x + \frac{1}{2}.

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