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Find the inverse of \newlinef(x)=14x7f(x)=\frac{1}{4x}-7

Full solution

Q. Find the inverse of \newlinef(x)=14x7f(x)=\frac{1}{4x}-7
  1. Set f(x)f(x) equal to yy: Set f(x)f(x) equal to yy.y=14x7y = \frac{1}{4x} - 7
  2. Swap x and y: Swap x and y to find the inverse.\newlinex=14y7x = \frac{1}{4y} - 7
  3. Solve for y: Solve for y.\newlinex+7=14yx + 7 = \frac{1}{4y}
  4. Multiply by 4y4y: Multiply both sides by 4y4y to get rid of the fraction.\newline4y(x+7)=14y(x + 7) = 1
  5. Distribute 4y4y: Distribute 4y4y on the left side.4yx+28y=14yx + 28y = 1
  6. Isolate y: Isolate y on one side.\newline28y=14yx28y = 1 - 4yx
  7. Factor out y: Factor out y from the left side.\newliney(28+4x)=1y(28 + 4x) = 1
  8. Divide both sides: Divide both sides by (28+4x)(28 + 4x) to solve for yy.y=1(28+4x)y = \frac{1}{(28 + 4x)}
  9. Write final expression: Write the final expression for the inverse function. f1(x)=1(28+4x)f^{-1}(x) = \frac{1}{(28 + 4x)}

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