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Let’s check out your problem:
Find the following trigonometric values.
\newline
Express your answers exactly.
\newline
cos
(
22
5
∘
)
=
\cos \left(225^{\circ}\right)=
cos
(
22
5
∘
)
=
\newline
□
\square
□
\newline
sin
(
22
5
∘
)
=
\sin \left(225^{\circ}\right)=
sin
(
22
5
∘
)
=
\newline
□
\square
□
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Home
Math Problems
Algebra 2
Csc, sec, and cot of special angles
Full solution
Q.
Find the following trigonometric values.
\newline
Express your answers exactly.
\newline
cos
(
22
5
∘
)
=
\cos \left(225^{\circ}\right)=
cos
(
22
5
∘
)
=
\newline
□
\square
□
\newline
sin
(
22
5
∘
)
=
\sin \left(225^{\circ}\right)=
sin
(
22
5
∘
)
=
\newline
□
\square
□
Identify Quadrant:
cos
(
225
°
)
\cos(225°)
cos
(
225°
)
is in the third quadrant where cosine is negative. Use the reference angle of
45
°
45°
45°
.
Use Reference Angle:
cos
(
225
°
)
=
−
cos
(
45
°
)
\cos(225°) = -\cos(45°)
cos
(
225°
)
=
−
cos
(
45°
)
because cosine is negative in the third quadrant.
Calculate Cosine:
cos
(
45
°
)
=
2
2
\cos(45°) = \frac{\sqrt{2}}{2}
cos
(
45°
)
=
2
2
. So,
cos
(
225
°
)
=
−
2
2
\cos(225°) = -\frac{\sqrt{2}}{2}
cos
(
225°
)
=
−
2
2
.
Identify Quadrant:
sin
(
225
°
)
\sin(225°)
sin
(
225°
)
is also in the third quadrant where sine is negative. Use the reference angle of
45
°
45°
45°
.
Use Reference Angle:
sin
(
225
°
)
=
−
sin
(
45
°
)
\sin(225°) = -\sin(45°)
sin
(
225°
)
=
−
sin
(
45°
)
because sine is negative in the third quadrant.
Calculate Sine:
sin
(
45
°
)
=
2
2
\sin(45°) = \frac{\sqrt{2}}{2}
sin
(
45°
)
=
2
2
. So,
sin
(
225
°
)
=
−
2
2
\sin(225°) = -\frac{\sqrt{2}}{2}
sin
(
225°
)
=
−
2
2
.
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0
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Evaluate. Write your answer in simplified, rationalized form. Do not round.
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cot
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0
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3
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The terminal side of an angle
θ
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(\frac{84}{85}, \frac{13}{85})
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. What is
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cos
(
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\newline
Write your answer in simplified, rationalized form.
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−
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θ
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∘
<
θ
<
9
0
∘
. Find the value of
θ
\theta
θ
in degrees.
\newline
tan
(
θ
)
=
0
\tan(\theta) = 0
tan
(
θ
)
=
0
\newline
Write your answer in simplified, rationalized form. Do not round.
\newline
θ
=
\theta =
θ
=
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∘
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∘
\newline
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Question
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\newline
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