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find the first derivative of sin(4X) \sin(4X)

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Q. find the first derivative of sin(4X) \sin(4X)
  1. Identify Function: Identify the function to differentiate.\newlineWe are given the function f(x)=sin(4x)f(x) = \sin(4x) and we need to find its first derivative, f(x)f'(x).
  2. Apply Chain Rule: Apply the chain rule for differentiation.\newlineThe chain rule states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. In this case, the outer function is sin(u)\sin(u) and the inner function is u=4xu = 4x.
  3. Differentiate Outer Function: Differentiate the outer function with respect to the inner function.\newlineThe derivative of sin(u)\sin(u) with respect to uu is cos(u)\cos(u).
  4. Differentiate Inner Function: Differentiate the inner function with respect to xx. The derivative of 4x4x with respect to xx is 44.
  5. Apply Chain Rule Result: Apply the chain rule by multiplying the results from Step 33 and Step 44.\newlinef(x)=cos(4x)×4f'(x) = \cos(4x) \times 4
  6. Simplify Final Answer: Simplify the expression if necessary.\newlineThe expression is already simplified, so we have the final answer.\newlinef(x)=4cos(4x)f'(x) = 4\cos(4x)

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