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Let’s check out your problem:
Find the distance between the two points.
\newline
(
8
,
−
8
)
and
(
−
5.2
,
−
8
)
(8,-8) \text { and }(-5.2,-8)
(
8
,
−
8
)
and
(
−
5.2
,
−
8
)
\newline
Answer:
\newline
Write an optional reasoning for your answer:
\newline
7
7
7
\newline
A
\newline
B
\newline
I
\newline
Q
0
Q_{0}
Q
0
\newline
sis
\newline
(
2
2
2
)
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Math Problems
Precalculus
Find the magnitude of a three-dimensional vector
Full solution
Q.
Find the distance between the two points.
\newline
(
8
,
−
8
)
and
(
−
5.2
,
−
8
)
(8,-8) \text { and }(-5.2,-8)
(
8
,
−
8
)
and
(
−
5.2
,
−
8
)
\newline
Answer:
\newline
Write an optional reasoning for your answer:
\newline
7
7
7
\newline
A
\newline
B
\newline
I
\newline
Q
0
Q_{0}
Q
0
\newline
sis
\newline
(
2
2
2
)
Calculate Coordinates Difference:
Calculate the difference in the x-coordinates (
Δ
x
\Delta x
Δ
x
) and y-coordinates (
Δ
y
\Delta y
Δ
y
).
\newline
Δ
x
=
−
5.2
−
8
=
−
13.2
\Delta x = -5.2 - 8 = -13.2
Δ
x
=
−
5.2
−
8
=
−
13.2
\newline
Δ
y
=
−
8
−
(
−
8
)
=
0
\Delta y = -8 - (-8) = 0
Δ
y
=
−
8
−
(
−
8
)
=
0
Use Distance Formula:
Use the distance formula:
distance
=
(
Δ
x
2
+
Δ
y
2
)
\text{distance} = \sqrt{(\Delta x^2 + \Delta y^2)}
distance
=
(
Δ
x
2
+
Δ
y
2
)
.
distance
=
(
(
−
13.2
)
2
+
0
2
)
\text{distance} = \sqrt{((-13.2)^2 + 0^2)}
distance
=
((
−
13.2
)
2
+
0
2
)
Calculate Squares and Sum:
Calculate the squares and sum them up.
\newline
d
i
s
t
a
n
c
e
=
174.24
+
0
distance = \sqrt{174.24 + 0}
d
i
s
t
an
ce
=
174.24
+
0
Take Square Root:
Take the square root to find the distance.
\newline
distance =
174.24
\sqrt{174.24}
174.24
\newline
distance =
13.2
13.2
13.2
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