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Let’s check out your problem:
Find the distance between the points
(
7
,
8
)
(7,8)
(
7
,
8
)
and
(
7
,
4
)
(7,4)
(
7
,
4
)
.
\newline
____ units
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Math Problems
Precalculus
Find the magnitude of a three-dimensional vector
Full solution
Q.
Find the distance between the points
(
7
,
8
)
(7,8)
(
7
,
8
)
and
(
7
,
4
)
(7,4)
(
7
,
4
)
.
\newline
____ units
Calculate Differences:
Calculate the difference in the
x
x
x
-coordinates and
y
y
y
-coordinates of the two points.
\newline
x
2
−
x
1
=
7
−
7
=
0
x_2 - x_1 = 7 - 7 = 0
x
2
−
x
1
=
7
−
7
=
0
\newline
y
2
−
y
1
=
4
−
8
=
−
4
y_2 - y_1 = 4 - 8 = -4
y
2
−
y
1
=
4
−
8
=
−
4
Use Distance Formula:
Use the distance formula:
Distance
=
(
x
2
−
x
1
)
2
+
(
y
2
−
y
1
)
2
\text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
Distance
=
(
x
2
−
x
1
)
2
+
(
y
2
−
y
1
)
2
.
\newline
Distance
=
(
0
)
2
+
(
−
4
)
2
\text{Distance} = \sqrt{(0)^2 + (-4)^2}
Distance
=
(
0
)
2
+
(
−
4
)
2
\newline
Distance
=
0
+
16
\text{Distance} = \sqrt{0 + 16}
Distance
=
0
+
16
\newline
Distance
=
16
\text{Distance} = \sqrt{16}
Distance
=
16
Simplify Square Root:
Simplify the square root to find the final distance. Distance =
4
4
4
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Rewrite in simplest terms:
6
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(
−
2
c
−
9
)
6 c-9(-2 c-9)
6
c
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)
\newline
Answer:
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Find the coordinates of the vertex of the following parabola algebraically. Write your answer as an
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(
−
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(
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\newline
Answer:
\newline
Submit Answer
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Question
2
2
2
. Given coordinates
A
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−
1
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,
B
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9
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1
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A(-1,-1), B(9,1)
A
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1
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,
B
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and
D
(
0
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4
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D(0,4)
D
(
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4
)
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C
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C
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A
B
C
D
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A
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Question
Find the distance between
P
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P(4,4)
P
(
4
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7
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Q(9,7)
Q
(
9
,
7
)
.
\newline
The distance between
P
P
P
and
Q
Q
Q
is
□
\square
□
.
\newline
(Simplify your answer. Type an exact answer using radicals as need
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Find the length and width op the quadrilateral with vertices at
(
6
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4
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(
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6
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7
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7
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6
6
6
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