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Find the distance between the points (3,7)(3,7) and (7,10)(7,10).\newline\newlineWrite your answer as a whole number or a fully simplified radical expression. Do not round.\newline\newline__\_\_ units

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Q. Find the distance between the points (3,7)(3,7) and (7,10)(7,10).\newline\newlineWrite your answer as a whole number or a fully simplified radical expression. Do not round.\newline\newline__\_\_ units
  1. Distance Formula: To find the distance between two points in a coordinate plane, we use the distance formula, which is derived from the Pythagorean theorem. The distance formula is: (x2x1)2+(y2y1)2\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}. For the points (3,7)(3,7) and (7,10)(7,10), we have (x1,y1)=(3,7)(x_1, y_1) = (3, 7) and (x2,y2)=(7,10)(x_2, y_2) = (7, 10). Let's calculate the distance using this formula.
  2. Calculate X-coordinate Difference: First, we calculate the difference in the x-coordinates: (x2x1)=(73)(x_2 - x_1) = (7 - 3). This gives us 44. Now we square this difference: (4)2=16(4)^2 = 16.
  3. Calculate Y-coordinate Difference: Next, we calculate the difference in the y-coordinates: (y2y1)=(107)(y_2 - y_1) = (10 - 7). This gives us 33. Now we square this difference: (3)2=9(3)^2 = 9.
  4. Add Squares of Differences: We now add the squares of the differences in the xx and yy coordinates: 16+9=2516 + 9 = 25.
  5. Find Distance: Finally, we take the square root of the sum to find the distance: 25=5\sqrt{25} = 5. Therefore, the distance between the points (3,7)(3,7) and (7,10)(7,10) is 55 units.

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