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Find the distance between the points (2,7)(2,7) and (5,3)(5,3).\newlineWrite your answer as a whole number or a fully simplified radical expression. Do not round.\newline__\_\_ units

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Q. Find the distance between the points (2,7)(2,7) and (5,3)(5,3).\newlineWrite your answer as a whole number or a fully simplified radical expression. Do not round.\newline__\_\_ units
  1. Given Points: We have: \newlinePoints: (2,7)(2, 7) and (5,3)(5, 3) \newlineFind the values of x1x_1, x2x_2, y1y_1, and y2y_2 from the given points. \newlinex1=2x_1 = 2 \newliney1=7y_1 = 7 \newlinex2=5x_2 = 5 \newliney2=3y_2 = 3
  2. Distance Formula: We know: \newlineDistance formula: d=(x2x1)2+(y2y1)2d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \newlinex1=2x_1 = 2, y1=7y_1 = 7, x2=5x_2 = 5, and y2=3y_2 = 3 \newlineSubstitute the values of x1x_1, y1y_1, x2x_2, y2y_2 in the distance formula. \newlined=(52)2+(37)2d = \sqrt{(5-2)^2 + (3-7)^2}
  3. Simplify Calculation: Simplify (52)2+(37)2(5-2)^2 + (3-7)^2. \newline(52)2+(37)2(5-2)^2 + (3-7)^2 \newline= 32+(4)23^2 + (-4)^2 \newline= 9+169 + 16 \newline= 2525
  4. Find Distance: We have: \newlined=25d = \sqrt{25} \newlineFind the distance between the points (2,7)(2,7) and (5,3)(5,3). \newline25=5\sqrt{25} = 5 \newlineDistance between the points (2,7)(2,7) and (5,3)(5,3) is 55 units.

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