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Find the distance between the points $(2,6)$ and $(10,6)$ . $\newline$ $\_\_\_\_$ units

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Find the magnitude of a three-dimensional vector

Full solution

Q. Find the distance between the points

(2,6)

and

(10,6)

.

\newline

\_\_\_\_

units

Calculate Coordinates Difference: Calculate the difference in $x$ -coordinates and $y$ -coordinates between the two points. $\newline$ $x_2 - x_1 = 10 - 2 = 8$ $\newline$ $y_2 - y_1 = 6 - 6 = 0$
Apply Distance Formula: Apply the distance formula: $\text{distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$ .
$\text{distance} = \sqrt{(8)^2 + (0)^2}$
$\text{distance} = \sqrt{64 + 0}$
$\text{distance} = \sqrt{64}$
$\text{distance} = 8$

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