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Find the discriminant.\newlinet2+9t+7=0t^2 + 9t + 7 = 0

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Full solution

Q. Find the discriminant.\newlinet2+9t+7=0t^2 + 9t + 7 = 0
  1. Identify values of aa, bb, cc: Identify the values of aa, bb, and cc by comparing the given equation t2+9t+7=0t^2 + 9t + 7 = 0 with the standard quadratic equation form ax2+bx+c=0ax^2 + bx + c = 0. Here, a=1a = 1, b=9b = 9, and bb00.
  2. Calculate discriminant using formula: Use the discriminant formula D=b2−4acD = b^2 - 4ac to calculate the discriminant of the quadratic equation.\newlineSubstitute 11 for aa, 99 for bb, and 77 for cc into the formula.\newlineD=(9)2−4×1×7D = (9)^2 - 4 \times 1 \times 7
  3. Find value of discriminant: Perform the calculations to find the value of the discriminant.\newlineD=81−4×7D = 81 - 4 \times 7\newlineD=81−28D = 81 - 28\newlineD=53D = 53

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