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Find the discriminant.\newline5s2+6s−1=05s^2 + 6s - 1 = 0

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Full solution

Q. Find the discriminant.\newline5s2+6s−1=05s^2 + 6s - 1 = 0
  1. Identify coefficients: Identify the coefficients aa, bb, and cc from the quadratic equation 5s2+6s−1=05s^2 + 6s - 1 = 0 by comparing it to the standard form ax2+bx+c=0ax^2 + bx + c = 0. In this case, a=5a = 5, b=6b = 6, and c=−1c = -1.
  2. Recall discriminant formula: Recall the formula for the discriminant of a quadratic equation, which is D=b2−4acD = b^2 - 4ac.
  3. Substitute values: Substitute the identified values into the discriminant formula: D=62−4×5×(−1)D = 6^2 - 4 \times 5 \times (-1).
  4. Calculate discriminant: Calculate the discriminant: D=36−4×5×(−1)=36+20=56D = 36 - 4 \times 5 \times (-1) = 36 + 20 = 56.

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