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Find the discriminant.\newline3x2+2x+5=03x^2 + 2x + 5 = 0

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Full solution

Q. Find the discriminant.\newline3x2+2x+5=03x^2 + 2x + 5 = 0
  1. Identify values: Identify the values of aa, bb, and cc by comparing the given quadratic equation 3x2+2x+5=03x^2 + 2x + 5 = 0 with the standard form ax2+bx+c=0ax^2 + bx + c = 0. Here, a=3a = 3, b=2b = 2, and c=5c = 5.
  2. Recall formula: Recall the formula for the discriminant of a quadratic equation, which is D=b2−4acD = b^2 - 4ac.
  3. Substitute values: Substitute the identified values of aa, bb, and cc into the discriminant formula.\newlineSo, D=(2)2−4×3×5D = (2)^2 - 4 \times 3 \times 5.
  4. Perform calculations: Perform the calculations to find the value of the discriminant.\newlineD=4−4×3×5D = 4 - 4 \times 3 \times 5\newlineD=4−60D = 4 - 60\newlineD=−56D = -56

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