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Find the derivative of the following function.

y=4^(2x^(5))
Answer: 
y^(')=

Find the derivative of the following function.\newliney=42x5 y=4^{2 x^{5}} \newlineAnswer: y= y^{\prime}=

Full solution

Q. Find the derivative of the following function.\newliney=42x5 y=4^{2 x^{5}} \newlineAnswer: y= y^{\prime}=
  1. Recognize composition of functions: First, we need to recognize that this is a composition of functions and we will need to use the chain rule to find the derivative. The chain rule states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function.
  2. Find derivative of outer function: The outer function is 4u4^u where u=2x5u = 2x^5. The derivative of 4u4^u with respect to uu is 4uln(4)4^u \cdot \ln(4) because the derivative of aua^u is auln(a)a^u \cdot \ln(a) where aa is a constant.
  3. Find derivative of inner function: The inner function is u=2x5u = 2x^5. The derivative of uu with respect to xx is 10x410x^4 because the derivative of xnx^n is nx(n1)n\cdot x^{(n-1)}.
  4. Apply chain rule: Now we apply the chain rule by multiplying the derivative of the outer function by the derivative of the inner function. This gives us:\newliney=(42x5ln(4))(10x4)y' = (4^{2x^5} \cdot \ln(4)) \cdot (10x^4)
  5. Simplify final answer: Simplify the expression to get the final answer:\newliney=10x44(2x5)ln(4)y' = 10x^4 \cdot 4^{(2x^5)} \cdot \ln(4)

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