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Find the derivative of h(x)=(x2+xtan(x))h(x)=(\frac{x^2+x}{\tan(x)})

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Q. Find the derivative of h(x)=(x2+xtan(x))h(x)=(\frac{x^2+x}{\tan(x)})
  1. Identify Functions: Let's identify the two functions that are being divided. The numerator is u(x)=x2+xu(x) = x^2 + x and the denominator is v(x)=tan(x)v(x) = \tan(x). We will need to find the derivatives of both functions.
  2. Find Derivatives: The derivative of the numerator u(x)=x2+xu(x) = x^2 + x is u(x)=2x+1u'(x) = 2x + 1.
  3. Apply Quotient Rule: The derivative of the denominator v(x)=tan(x)v(x) = \tan(x) is v(x)=sec2(x)v'(x) = \sec^2(x), since the derivative of tan(x)\tan(x) is sec2(x)\sec^2(x).
  4. Calculate h(x)h'(x): Now, we can apply the quotient rule to find the derivative of h(x)h(x). The quotient rule states that (uv)=vuuvv2(\frac{u}{v})' = \frac{v \cdot u' - u \cdot v'}{v^2}. Let's apply this to our functions.
  5. Simplify Expression: Using the quotient rule, we get h(x)=tan(x)(2x+1)(x2+x)sec2(x)tan2(x)h'(x) = \frac{\tan(x) \cdot (2x + 1) - (x^2 + x) \cdot \sec^2(x)}{\tan^2(x)}.
  6. Final Derivative: We can simplify the expression by distributing and combining like terms if possible.
  7. Final Derivative: We can simplify the expression by distributing and combining like terms if possible.However, there is no further simplification that can be done without expanding tan(x)\tan(x) and sec2(x)\sec^2(x) in terms of sine and cosine, which is not necessary for finding the derivative. So, the derivative of h(x)h(x) is h(x)=tan(x)(2x+1)(x2+x)sec2(x)tan2(x)h'(x) = \frac{\tan(x) \cdot (2x + 1) - (x^2 + x) \cdot \sec^2(x)}{\tan^2(x)}.

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