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Find the derivative of \newlinef(x)f(x).\newlinef(x)=exxf(x)=\frac{e^{x}}{x}

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Q. Find the derivative of \newlinef(x)f(x).\newlinef(x)=exxf(x)=\frac{e^{x}}{x}
  1. Identify Function: Identify the function that needs differentiation. The function is f(x)=exxf(x) = \frac{e^x}{x}, which is a quotient of two functions.
  2. Use Quotient Rule: Recognize that we need to use the quotient rule for differentiation because we have a function in the form of g(x)h(x)\frac{g(x)}{h(x)}, where g(x)=exg(x) = e^x and h(x)=xh(x) = x.
  3. Recall Quotient Rule: Recall the quotient rule: (ddx)[g(x)h(x)]=g(x)h(x)g(x)h(x)[h(x)]2(\frac{d}{dx})[\frac{g(x)}{h(x)}] = \frac{g'(x)h(x) - g(x)h'(x)}{[h(x)]^2}. We will apply this rule to find the derivative of f(x)f(x).
  4. Differentiate Numerator: Differentiate the numerator g(x)=exg(x) = e^x. The derivative of exe^x with respect to xx is exe^x.
  5. Differentiate Denominator: Differentiate the denominator h(x)=xh(x) = x. The derivative of xx with respect to xx is 11.
  6. Apply Quotient Rule: Apply the quotient rule using the derivatives from the previous steps. The derivative of f(x)f(x) is f(x)=ex1ex1x2f'(x) = \frac{e^x \cdot 1 - e^x \cdot 1}{x^2}.
  7. Simplify Expression: Simplify the expression. The derivative of f(x)f(x) simplifies to f(x)=exexx2f'(x) = \frac{e^x - e^x}{x^2}, which further simplifies to f(x)=0x2f'(x) = \frac{0}{x^2}.

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