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Find the derivative of f(x) f(x) f(x)=e(x+1) f(x)=e^{(x+1)}

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Q. Find the derivative of f(x) f(x) f(x)=e(x+1) f(x)=e^{(x+1)}
  1. Find Derivative of e(x+1)e^{(x+1)}: We need to find the derivative of the function f(x)=e(x+1)f(x) = e^{(x+1)}. The derivative of eue^u, where uu is a function of xx, is eue^u times the derivative of uu with respect to xx. In this case, u=x+1u = x + 1.
  2. Apply Chain Rule: The derivative of u=x+1u = x + 1 with respect to xx is 11, since the derivative of a constant is 00 and the derivative of xx is 11.
  3. Calculate Final Derivative: Applying the chain rule, the derivative of f(x)f(x) with respect to xx is e(x+1)e^{(x+1)} times the derivative of (x+1)(x+1) with respect to xx, which we found to be 11.
  4. Calculate Final Derivative: Applying the chain rule, the derivative of f(x)f(x) with respect to xx is e(x+1)e^{(x+1)} times the derivative of (x+1)(x+1) with respect to xx, which we found to be 11.Therefore, the derivative of f(x)=e(x+1)f(x) = e^{(x+1)} is simply e(x+1)×1e^{(x+1)} \times 1, which simplifies to e(x+1)e^{(x+1)}.

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