Q. 9. Find the derivative of f(x)=8sec(x)+6x4cos(x).
Identify Components: Identify the components of the function that need to be differentiated.f(x)=8sec(x)+6x4cos(x) consists of two terms: 8sec(x) and 6x4cos(x). We will need to use the sum rule for derivatives, which states that the derivative of a sum is the sum of the derivatives.
Differentiate First Term: Differentiate the first term, 8sec(x). The derivative of sec(x) is sec(x)tan(x), so the derivative of 8sec(x) is 8sec(x)tan(x).
Differentiate Second Term: Differentiate the second term, 6x4cos(x). This term requires the product rule for derivatives, which states that the derivative of a product of two functions is the derivative of the first function times the second function plus the first function times the derivative of the second function. Let u=6x4 and v=cos(x), then dxdu=24x3 and dxdv=−sin(x).
Apply Product Rule: Apply the product rule to 6x4cos(x). Using the product rule, the derivative of 6x4cos(x) is (dxdu)v+u(dxdv)=(24x3)cos(x)+6x4(−sin(x)).
Combine Derivatives: Combine the derivatives of both terms.The derivative of f(x) is the sum of the derivatives from Step 2 and Step 4. Therefore, f′(x)=8sec(x)tan(x)+(24x3)cos(x)−6x4sin(x).
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