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Find the derivative of 
f(x)=8sec(x)+6x^(4)cos(x).

99. Find the derivative of f(x)=8sec(x)+6x4cos(x) f(x)=8 \sec (x)+6 x^{4} \cos (x) .

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Q. 99. Find the derivative of f(x)=8sec(x)+6x4cos(x) f(x)=8 \sec (x)+6 x^{4} \cos (x) .
  1. Identify Components: Identify the components of the function that need to be differentiated.\newlinef(x)=8sec(x)+6x4cos(x)f(x) = 8\sec(x) + 6x^{4}\cos(x) consists of two terms: 8sec(x)8\sec(x) and 6x4cos(x)6x^{4}\cos(x). We will need to use the sum rule for derivatives, which states that the derivative of a sum is the sum of the derivatives.
  2. Differentiate First Term: Differentiate the first term, 8sec(x)8\sec(x). The derivative of sec(x)\sec(x) is sec(x)tan(x)\sec(x)\tan(x), so the derivative of 8sec(x)8\sec(x) is 8sec(x)tan(x)8\sec(x)\tan(x).
  3. Differentiate Second Term: Differentiate the second term, 6x4cos(x)6x^{4}\cos(x). This term requires the product rule for derivatives, which states that the derivative of a product of two functions is the derivative of the first function times the second function plus the first function times the derivative of the second function. Let u=6x4u = 6x^{4} and v=cos(x)v = \cos(x), then dudx=24x3\frac{du}{dx} = 24x^{3} and dvdx=sin(x)\frac{dv}{dx} = -\sin(x).
  4. Apply Product Rule: Apply the product rule to 6x4cos(x)6x^{4}\cos(x). Using the product rule, the derivative of 6x4cos(x)6x^{4}\cos(x) is (dudx)v+u(dvdx)=(24x3)cos(x)+6x4(sin(x))(\frac{du}{dx})v + u(\frac{dv}{dx}) = (24x^{3})\cos(x) + 6x^{4}(-\sin(x)).
  5. Combine Derivatives: Combine the derivatives of both terms.\newlineThe derivative of f(x)f(x) is the sum of the derivatives from Step 22 and Step 44. Therefore, f(x)=8sec(x)tan(x)+(24x3)cos(x)6x4sin(x)f'(x) = 8\sec(x)\tan(x) + (24x^{3})\cos(x) - 6x^{4}\sin(x).

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