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Find the coordinates of the vertex of the following parabola algebraically. Write your answer as an 
(x,y) point.

y=x^(2)+4
Answer:

Find the coordinates of the vertex of the following parabola algebraically. Write your answer as an (x,y) (x, y) point.\newliney=x2+4 y=x^{2}+4 \newlineAnswer:

Full solution

Q. Find the coordinates of the vertex of the following parabola algebraically. Write your answer as an (x,y) (x, y) point.\newliney=x2+4 y=x^{2}+4 \newlineAnswer:
  1. Use Vertex Formula: To find the vertex of a parabola in the form y=ax2+bx+cy = ax^2 + bx + c, we can use the vertex formula x=b2ax = -\frac{b}{2a}. In this equation, y=x2+4y = x^2 + 4, a=1a = 1 and b=0b = 0, since there is no xx term.
  2. Substitute Values: We substitute a=1a = 1 and b=0b = 0 into the vertex formula to find the xx-coordinate of the vertex.\newlinex=b2a=021=0x = -\frac{b}{2a} = -\frac{0}{2\cdot 1} = 0
  3. Calculate Y-coordinate: Now that we have the xx-coordinate of the vertex, we can substitute it back into the original equation to find the yy-coordinate.y=x2+4=02+4=4y = x^2 + 4 = 0^2 + 4 = 4
  4. Find Vertex Coordinates: The coordinates of the vertex are (x,y)=(0,4)(x, y) = (0, 4).

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