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Find the average value of the function 
f(x)=(8)/(x-3) from 
x=5 to 
x=7. Write your answer as the logarithm of a single number in simplest form.
Answer: 
ln(◻)

Find the average value of the function f(x)=8x3 f(x)=\frac{8}{x-3} from x=5 x=5 to x=7 x=7 . Write your answer as the logarithm of a single number in simplest form.\newlineAnswer: ln() \ln (\square)

Full solution

Q. Find the average value of the function f(x)=8x3 f(x)=\frac{8}{x-3} from x=5 x=5 to x=7 x=7 . Write your answer as the logarithm of a single number in simplest form.\newlineAnswer: ln() \ln (\square)
  1. Set Up Integral: To find the average value of a continuous function f(x)f(x) on the interval [a,b][a, b], we use the formula:\newlineAverage value = (1/(ba))×abf(x)dx(1/(b-a)) \times \int_{a}^{b} f(x) \, dx\newlineHere, a=5a = 5 and b=7b = 7, so we need to integrate f(x)=(8)/(x3)f(x) = (8)/(x-3) from x=5x = 5 to x=7x = 7 and then multiply by 1/(75)1/(7-5).
  2. Solve Integral: First, let's set up the integral:\newlineAverage value = (1/(75))×578x3dx(1/(7-5)) \times \int_{5}^{7} \frac{8}{x-3} \,dx\newlineThis simplifies to:\newlineAverage value = (1/2)×578x3dx(1/2) \times \int_{5}^{7} \frac{8}{x-3} \,dx
  3. Evaluate Integral: To integrate 8x3\frac{8}{x-3}, we recognize this as a simple logarithmic integration problem. The integral of 1udu\frac{1}{u} du is lnu\ln|u|, so the integral of 8x3dx\frac{8}{x-3} dx is 8lnx38\ln|x-3|. Now we need to evaluate this from x=5x = 5 to x=7x = 7.
  4. Simplify Expression: Evaluating the integral, we get:\newline(12)×[8ln738ln53](\frac{1}{2}) \times [8\ln|7-3| - 8\ln|5-3|]\newlineThis simplifies to:\newline(12)×[8ln(4)8ln(2)](\frac{1}{2}) \times [8\ln(4) - 8\ln(2)]
  5. Apply Logarithm Properties: We can simplify the expression using logarithm properties. The difference of logarithms is the logarithm of the quotient:\newline(12)×8ln(42)(\frac{1}{2}) \times 8\ln(\frac{4}{2})\newlineSince 4/24/2 is 22, this further simplifies to:\newline(12)×8ln(2)(\frac{1}{2}) \times 8\ln(2)
  6. Final Result: Multiplying through by (12)×8(\frac{1}{2}) \times 8 gives us:\newline4ln(2)4\ln(2)\newlineThis is the average value of the function f(x)f(x) from x=5x = 5 to x=7x = 7, expressed as the logarithm of a single number in simplest form.

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