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Find 
(dy)/(dx) if 
y=5sin x^(2)

Find dydx \frac{d y}{d x} if y=5sinx2 y=5 \sin x^{2}

Full solution

Q. Find dydx \frac{d y}{d x} if y=5sinx2 y=5 \sin x^{2}
  1. Identify Function: Let's identify the function we need to differentiate. The function is y=5sin(x2)y = 5\sin(x^2). We will use the chain rule to differentiate this function because it is a composition of two functions: the sine function and the function x2x^2.
  2. Apply Chain Rule: The chain rule states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. In this case, the outer function is 5sin(u)5\sin(u) where u=x2u = x^2, and the inner function is x2x^2.
  3. Differentiate Outer Function: First, we differentiate the outer function with respect to uu. The derivative of 5sin(u)5\sin(u) with respect to uu is 5cos(u)5\cos(u), because the derivative of sin(u)\sin(u) is cos(u)\cos(u) and we have a constant multiple of 55.
  4. Differentiate Inner Function: Next, we differentiate the inner function with respect to xx. The derivative of x2x^2 with respect to xx is 2x2x, because we apply the power rule which states that the derivative of xnx^n is nx(n1)n\cdot x^{(n-1)}.
  5. Apply Chain Rule: Now we apply the chain rule by multiplying the derivative of the outer function by the derivative of the inner function. This gives us dydx=5cos(u)2x\frac{dy}{dx} = 5\cos(u) \cdot 2x, where u=x2u = x^2.
  6. Substitute Back: Substitute uu back into the equation to get the derivative in terms of xx. This gives us dydx=5cos(x2)2x\frac{dy}{dx} = 5\cos(x^2) \cdot 2x.
  7. Simplify Final Answer: Finally, we simplify the expression to get the final answer. (dydx=10xcos(x2))(\frac{dy}{dx} = 10x \cdot \cos(x^2)).

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