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Find all solutions with 0°≤θ≤180°0°\leq\theta\leq180°. Give the exact answer(s) in simplest form. If there are multiple answers, separate them with commas. –15cos⁡(θ)–152=0– 15\cos(\theta)– \frac{15}{2} =0

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Full solution

Q. Find all solutions with 0°≤θ≤180°0°\leq\theta\leq180°. Give the exact answer(s) in simplest form. If there are multiple answers, separate them with commas. –15cos⁡(θ)–152=0– 15\cos(\theta)– \frac{15}{2} =0
  1. Simplify Equation: Simplify the equation −15cos⁡(θ)−152=0-15\cos(\theta) - \frac{15}{2} = 0 by adding 152\frac{15}{2} to both sides.
  2. Divide and Isolate: Divide both sides by −15-15 to isolate cos⁡(θ)\cos(\theta).
  3. Find θ\theta: Find θ\theta such that cos⁡(θ)=−12\cos(\theta) = -\frac{1}{2} within the interval 0∘0^\circ to 180∘180^\circ.
  4. Check Range: Check if 240°240° is within the given range 0°0° to 180°180°.

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