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Find all of the cube roots of -1 and write the answers in rectangular (standard) form.

Find all of the cube roots of 1-1 and write the answers in rectangular (standard) form.

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Q. Find all of the cube roots of 1-1 and write the answers in rectangular (standard) form.
  1. Identify Equation: Identify the equation for finding cube roots of a number.\newlineTo find the cube roots of 1-1, we solve the equation x3=1x^3 = -1.
  2. Solve Real Cube Root: Solve for the real cube root.\newlineThe real cube root of 1-1 is x=1x = -1, because (1)3=1(-1)^3 = -1.
  3. Find Complex Roots: Find the complex cube roots using the polar form of complex numbers.\newlineExpress 1-1 in polar form: 1-1 = 11*(cos(π) + i*sin(π)).\newlineUsing De Moivre's Theorem, the nth roots are given by:\newlinexk=r1/n(cos(θ+2kπn)+isin(θ+2kπn)) x_k = r^{1/n} \left( \cos\left(\frac{\theta + 2k\pi}{n}\right) + i\sin\left(\frac{\theta + 2k\pi}{n}\right) \right) \newlinefor k = 00, 11, ..., n1-1, where n = 33 here.
  4. Calculate First Root: Calculate the first complex cube root (k=11).\newlinex1=11/3(cos(π+2π3)+isin(π+2π3)) x_1 = 1^{1/3} \left( \cos\left(\frac{\pi + 2\pi}{3}\right) + i\sin\left(\frac{\pi + 2\pi}{3}\right) \right) \newlinex1=cos(3π3)+isin(3π3) x_1 = \cos\left(\frac{3\pi}{3}\right) + i\sin\left(\frac{3\pi}{3}\right) \newlinex1=cos(π)+isin(π) x_1 = \cos(\pi) + i\sin(\pi) \newlinex1=1+0i x_1 = -1 + 0i

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