Resources

Resources

Bytelearn - cat image with glasses

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Find all angles,
0^(@) <= theta < 360^(@), that satisfy the equation below, to the nearest tenth of a degree.

tan^(2)theta-tan theta=0
Answer:
theta=

Find all angles, $0^{\circ} \leq \theta<360^{\circ}$ , that satisfy the equation below, to the nearest tenth of a degree. $\newline$ $\tan ^{2} \theta-\tan \theta=0$ $\newline$ Answer: $\theta=$

View step-by-step help

View step-by-step help

Find roots using a calculator

Full solution

Q. Find all angles,

0^{\circ} \leq \theta<360^{\circ}

, that satisfy the equation below, to the nearest tenth of a degree.

\newline

\tan ^{2} \theta-\tan \theta=0

\newline

Answer:

\theta=

Factor and Solve: We are given the equation $\tan^2\theta - \tan \theta = 0$ . To solve for $\theta$ , we first factor the left side of the equation. $\newline$ $\tan \theta * (\tan \theta - 1) = 0$ $\newline$ This gives us two separate equations to solve: $\newline$ $1$ ) $\tan \theta = 0$ $\newline$ $2$ ) $\tan \theta - 1 = 0$
Solve $\tan \theta = 0$ : Let's solve the first equation $\tan \theta = 0$ . The tangent of an angle is zero at $0$ degrees and $180$ degrees within the range of $0$ to $360$ degrees. So, $\theta = 0$ degrees and $\theta = 180$ degrees.
Solve $\tan \theta - 1 = 0$ : Now, let's solve the second equation $\tan \theta - 1 = 0$ . This simplifies to $\tan \theta = 1$ . The tangent of an angle is equal to $1$ at $45$ degrees and $225$ degrees within the range of $0$ to $360$ degrees. So, $\theta = 45$ degrees and $\theta = 225$ degrees.
Final Angles: We have found all the angles that satisfy the given equation: $\theta = 0$ degrees, $\theta = 45$ degrees, $\theta = 180$ degrees, and $\theta = 225$ degrees. These are the angles to the nearest tenth of a degree.

More problems from Find roots using a calculator

Question

Find the real-number root.

\newline

\sqrt{16}

\newline

\newline

Write your answer in simplified form.

\newline

\_\_\_\_

Posted 2 months ago

Question

Find the real-number root.

\newline

\sqrt{\frac{9}{16}}

\newline

Simplify your answer and write it as a decimal or as a proper or improper fraction.

\newline

\_\_\_\_\_

Posted 2 months ago

Question

Find the real-number root using a calculator. Round your answer to the nearest thousandth.

\newline

\newline

Posted 2 months ago

Question

Multiply. Write your answer in simplest form.

\newline

\sqrt{273} \times \sqrt{42}

\newline

Posted 1 month ago

Question

\newline

\sqrt{\frac{63}{4}}

\newline

Posted 2 months ago

Question

Simplify. Rationalize the denominator.

\newline

\frac{-4}{9 - \sqrt{2}}

\newline

Posted 2 months ago

Question

z

\newline

16 = \sqrt{z}

\newline

z =

Posted 2 months ago

Question

Simplify the radical expression.

\sqrt{14x^{14}}

Write your answer in the form

A

\sqrt{B}

A\sqrt{B}

A

B

are constants or expressions in

x

. Use at most one radical in your answer, and at most one absolute value symbol in your expression for

A

Posted 2 months ago

Question

Simplify the radical expression.

\newline

\sqrt{12x^{12}}

\newline

Write your answer in the form

A

\sqrt{B}

A\sqrt{B}

A

B

are constants or expressions in

x

. Use at most one radical in your answer, and at most one absolute value symbol in your expression for

A

\newline

\underline{\hspace{3cm}}

Posted 2 months ago

Question

What is the value of

\sin \left(\frac{5 \pi}{6}\right) ?

\newline

1

\newline

-\frac{\sqrt{3}}{2}

\newline

-\frac{\sqrt{2}}{2}

\newline

\frac{1}{2}

\newline

150

Posted 4 months ago