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Find
A nn B and
A uu B from the following Venn diagrams.
(a)
(b)
(c)

Find $A \cap B$ and $A \cup B$ from the following Venn diagrams. (a) (b) (c)

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Sin, cos, and tan of special angles

Full solution

Q. Find

A \cap B

and

A \cup B

from the following Venn diagrams. (a) (b) (c)

Identify Elements: Identify the elements in each set from the Venn diagrams;
Calculate $A \cap B$ : Calculate $A \cap B$ (intersection of $A$ and $B$ ) for each diagram;
Calculate $A \cup B$ : Calculate $A \cup B$ (union of $A$ and $B$ ) for each diagram;

More problems from Sin, cos, and tan of special angles

Question

Marco's class is painting a mural on the side of their school. The mural covers a

3 \frac{1}{2} \mathrm{~m}

high, rectangular wall. It has an area of

28 \mathrm{~m}^{2}

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What is the length of the mural?

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Question

A cup of hot coffee has been left to cool in a room with an ambient temperature of

21^{\circ} \mathrm{C}

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The relationship between the elapsed time,

m

, in minutes, since the coffee was left to cool, and the temperature of the coffee,

T

{ }^{\circ} \mathrm{C}

, is modeled by the following function.

\newline

T(m)=21+74 \cdot 10^{-0.03 m}

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What will the temperature of the coffee be after

10

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Round your answer, if necessary, to the nearest hundredth.

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{ }^{\circ} C

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Question

Takumi plants a tree in his backyard and studies how the number of branches grows over time.

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He predicts that the relationship between

N

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t

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N=5 \cdot 10^{0.3 t}

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Give an exact answer expressed as a base

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Question

g(x)=2^{x}

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Can we use the mean value theorem to say the equation

g^{\prime}(x)=16

has a solution where

3<x<5

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1

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(A) No, since the function is not differentiable on that interval.

\newline

(B) No, since the average rate of change of

g

over the interval

3 \leq x \leq 5

1 \overline{6}

\newline

(C) Yes, both conditions for using the mean value theorem have been met.

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Question

\frac{d y}{d t}=2 t+3 \text { and } y(1)=6

\newline

t

y=0

\newline

Choose all answers that apply:

\newline

t=-1

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t=-3

\newline

t=0

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t=-4

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t=1

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t=-2

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Question

y=x^{13}

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