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Fill in the hubbles to indicate the number of solutions for each equation.
Solution
One
Infinitely
Many
Solution
Solutions

5(2m-5)=8m-25+2m

Fill in the hubbles to indicate the number of solutions for each equation.\newlineSolution\newlineOne\newlineInfinitely\newlineMany\newlineSolution\newlineSolutions\newline5(2m5)=8m25+2m 5(2 m-5)=8 m-25+2 m

Full solution

Q. Fill in the hubbles to indicate the number of solutions for each equation.\newlineSolution\newlineOne\newlineInfinitely\newlineMany\newlineSolution\newlineSolutions\newline5(2m5)=8m25+2m 5(2 m-5)=8 m-25+2 m
  1. Combine Like Terms: Now, let's combine like terms on the right side of the equation: 8m+2m8m + 2m gives us 10m10m. So the equation simplifies to 10m25=10m2510m - 25 = 10m - 25.
  2. Subtract 10m10m: Next, we can subtract 10m10m from both sides to try and isolate the variable mm. But when we do that, we get 25=25-25 = -25, which means the mm terms cancel out.
  3. Infinitely Many Solutions: Since we're left with a true statement that doesn't contain the variable mm, this means that any value for mm will satisfy the equation.\newlineTherefore, the equation has infinitely many solutions.

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