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Factor.\newlinew22w+1w^2 - 2w + 1

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Q. Factor.\newlinew22w+1w^2 - 2w + 1
  1. Check for Perfect Square Trinomial: Determine if the quadratic can be factored as a perfect square trinomial. A perfect square trinomial is in the form (ab)2=a22ab+b2(a - b)^2 = a^2 - 2ab + b^2. We can compare w22w+1w^2 - 2w + 1 to the form a22ab+b2a^2 - 2ab + b^2 to see if it matches.
  2. Identify aa and bb: Identify aa and bb in the expression w22w+1w^2 - 2w + 1. Here, a=wa = w and b=1b = 1 because (w)2=w2(w)^2 = w^2 and (1)2=1(1)^2 = 1. The middle term 2w-2w should be equal to bb00, which is bb11.
  3. Confirm Trinomial Type: Confirm that the expression is a perfect square trinomial.\newlineSince w2w^2 is the square of ww, 11 is the square of 11, and 2w-2w is twice the product of ww and 11, the expression w22w+1w^2 - 2w + 1 is indeed a perfect square trinomial.
  4. Factor Using Formula: Factor the expression using the perfect square trinomial formula.\newlineThe factored form of w22w+1w^2 - 2w + 1 is (w1)2(w - 1)^2 because (w1)(w1)(w - 1)(w - 1) gives w2ww+1w^2 - w - w + 1, which simplifies to w22w+1w^2 - 2w + 1.