Resources

Resources

Bytelearn - cat image with glasses

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Factor the expression completely.

x^(2)y-x^(5)
Answer:

Factor the expression completely. $\newline$ $x^{2} y-x^{5}$ $\newline$ Answer:

View step-by-step help

View step-by-step help

Solve equations with variable exponents

Full solution

Q. Factor the expression completely.

\newline

x^{2} y-x^{5}

\newline

Answer:

Identify Common Factor: Identify the common factor in both terms of the expression $x^{2}y - x^{5}$ . Both terms have an ' $x$ ' raised to a power, so we can factor out the lowest power of ' $x$ ' which is $x^{2}$ .
Factor Out Common Factor: Factor out the common factor $x^{2}$ from the expression. $\newline$ $x^{2}y - x^{5} = x^{2}(y - x^{3})$
Check for Further Factoring: Check to see if the remaining expression inside the parentheses can be factored further. $\newline$ The expression inside the parentheses is $y - x^{3}$ , which does not have a common factor and is not a special product that can be factored further.

More problems from Solve equations with variable exponents

Question

Write the expression using an exponent.

\newline

2 \times 2

\newline

Posted 2 months ago

Question

Evaluate the expression.

4 - 4^2

Posted 2 months ago

Question

x^2 = 4

Posted 1 month ago

Question

x^2 = 9

Posted 3 months ago

Question

\newline

x^2 = 0

\newline

Write your answer in simplified, rationalized form.

\newline

x =

x =

Posted 3 months ago

Question

x

\newline

8 = 2^x

\newline

x =

Posted 3 months ago

Question

x

\newline

6 = 7^x

\newline

x =

Posted 3 months ago

Question

Select the equivalent expression.

\newline

((8^{-5})/(2^{-2}))^{-4}=?

\newline

1

\newline

\newline

(8^{20})/(2^{8})

\newline

\newline

(2^{6})/(8^{9})

\newline

\newline

(1)/(8\cdot 2^{2})

Posted 4 days ago

Question

Select the equivalent expression.

\newline

\left(\frac{b^{7}}{4^{5}}\right)^{-3}=\,?

\newline

1

\newline

\frac{b^{21}}{4^{15}}

\newline

\frac{4^{15}}{b^{21}}

\newline

b^{-21}\cdot 4^{-15}

Posted 1 month ago

Question

Select the equivalent expression.

\newline

(3^{3}\cdot6^{6})^{-3}=

\newline

1

\newline

\frac{1}{3^{9}\cdot6^{18}}

\newline

\frac{6^{18}}{3^{9}}

\newline

\frac{3^{9}}{6^{18}}

Posted 1 month ago